The Math Test of the SAT is compromised of 58 questions broken into two sections one is non-calculator with 20 questions (25 minutes) and the second is calculator with 38 questions (55 minutes). These 2 sections are designed to assess students’ ability to solve real world problems in the following four key areas:
SAT数学考试有58道题，分为两部分:一是非计算器，20道(25分钟); 二是计算器，38道(55分钟)。这两个部分旨在评估学生在以下四个关键领域解决现实问题的能力:
The Heart of Algebra
Problem Solving and Data Analysis
Passport to Advanced Mathematics
Additional Topics in Mathematics.
代数的核心
解决问题和数据分析
高等数学
数学中的其他主题
The test is mostly multiple-choice; students may select from four possible choices. Correct answers award one-point and incorrect answers or leaving a question blank will neither award nor deduct points.
There are free response questions at the ends of both sections- five non-calculator questions and eight calculator questions.
Students should take their time on easy questions to earn as many points as possible. If students are unsure of an answer the best course of action is to keep moving forward and return to the problem later if time allows them to do so.
考试主要是多项选择题; 学生可以从四个选项中进行选择。答对一分，答错或留空不扣分。
在两个部分的末尾都有不硬性要求作答的问题——5个非计算器问题和8个计算器问题。
学生应该把时间花在简单的问题上，以尽可能多的获得分数。如果学生不确定答案，最好的做法是继续前进，如果时间允许，稍后再回到问题上。
Here is an example SAT question:
以下是一道SAT的例题
How many solutions are there to the system of equations above?
这个方程组有多少个答案呢？
A) There are exactly 4 solutions. 4个
B) There are exactly 2 solutions. 2个
C) There is exactly 1 solution. 1个
D) There are no solutions. 没有答案
There are many ways to solve systems of equations, we will use a method called substitution as it is effective in almost all cases. This method is fast and effective and we can do it without a calculator.
解方程组有很多方法，我们将使用一种替换的方法，因为它在几乎所有情况下都是有效的。这种方法快速有效，不用计算器也能算出来。
To solve this system of equations, we must first rearrange the second equation into a form where y is the subject of the equation.
要解这个方程组，我们必须先把第二个方程重新排列成以y为主的形式
We have done this by adding 5x to both sides of the equation and taking away 8 from both sides of the equation.
我们在方程两边同时加上5x，然后从方程两边同时减去8来得到以上化简。
We can then replace y in our first equation with the new expression we have just found.
然后我们可以用我们刚刚找到的新表达式替换第一个方程中的y。
From here, we will rearrange the equation into a clearer form. We do this by taking 5x away and adding 8 to both sides of the equation.
现在，我们把方程重新整理成更清晰的形式。在方程两边同时减去5x加上8。
We will then use factorisation to allow us to solve the equation. We are looking for numbers which multiply together to make +1 and they must also add together to make -2. The only numbers which satisfy these two conditions are -1 and -1.
然后用因式分解来解这个方程。我们要找的是相乘得到+1和相加得到-2的两个数。唯一满足这两个条件的数是-1和-1。
From here we can solve the equation by setting each individual bracket equal to zero.
通过让每个括号里的式子等于零来解这个方程。
and
As you can see, these are the same.
We can then see that the equation will only have one solution. And by solving the equation we can see the solution will be:
如你所见，它们是一样的。
我们可以发现方程只有一个解，通过解这个方程我们得出解是:
Therefore, the correct answer is C.
所以，正确答案是C.
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